2020 Updated Electronics Shop Hackerrank Solution in by Coding Demons

For better understanding refer  YouTube Tutorial Video  

LOGIC

• Take array size (N)
• Input array (A)
• Sort the array.
•  Set sock pair counter to 0 (C=0) and sock frequency counter to 1 (T=0)
• Check for match and increment frequrncy.
• Check the no of pairs for each frequency.
• Print the final pair count.

CODE

/***SOLUTION BY CODING DEMONS***/

#include <bits/stdc++.h>

using namespace std;

int main () {

int n;         //array size

cin>>n;              

int a[n];                    

for (int i=0;i<n;i++){   

 cin>>a[i];      

//input array

       

}                       

//sorting the array

int m=sizeof(a)/sizeof(a[0]);     

sort(a,a+m);                     

int c=0;    //set counter to 0

int t=1;  //frequency count set to 1

int i=0; 

                        

while (i<n){                    

 for (int j=i+1;j<n;j++){   

  int x=a[i];           

  int y=a[j];    

      

if (x==y){      //frequency count

  t++;           

  }                

 } 

                 

 c=c+t/2;   //pair check

 i=i+t;     //set i to the next sock

 t=1;    //set t=1 to count 

          //next sock pairs

}       

cout<<c;    //print the total pairs

}

/********END********/

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