C++ program to search a given element in an array

        The below program simply takes all the inputs from the user and prints "PRESENT" if the element is found in the array and prints "ABSENT" if the element is not found in the array.

        This code is a simple execution of "The Linear Search Algorithm" in C++. 

Code

#include <iostream>

using namespace std;

int main()

{

    int n;                              //array size

    cin>>n;

    

    int a[n];                       //array declaration

    

    for(int i=0;i<n;i++){           //reading array

        cin>>a[i];

    }

    int s;

    cout<<"Enter an element to search "<<endl;

    cin>>s;

    

    int flag=0;                 //initially taking as not found

    

    for(int i=0;i<n;i++){           //searching the element via loop

        if(a[i]==s){                //if found update flag to 1

            flag=1;

        }

    }

    

    if(flag==1){                    //element found print PRESENT

        cout<<"PRESENT";

    }

    else{                           //element not found print ABSENT

        cout<<"ABSENT";

    }

    return 0;

}

Input

5

1 2 3 4 5

Output

Enter an element to search 

3

PRESENT

Input

5

1 2 3 4 5

Output

Enter an element to search 

6

ABSENT