C++ Solution: Taum & B'day Hackerrank

Taum & B'day

Code

#include<bits/stdc++.h>

using namespace std;

int main()

{

    int t,i;

    cin>>t; // input no of test cases

    for(i=0;i<t;i++)

    {

        long int b,w,bc,wc,z,total;

        cin>>b>>w>>bc>>wc>>z; // taking input requirements

        if((bc+z)<wc) // if cost of purchasing a black gift and converting it into white is less than the actual cost then he will do the same hence the cost is reset to which he buys the gift

        {

            wc=bc+z;

        }

        else if((wc+z)<bc) // if cost of purchasing a white gift and converting it into black is less than the actual cost then he will do the same hence the cost is reset to which he buys the gift

        {

            bc=wc+z;

        }

        total=b*bc+w*wc; // finally calculate the total cost by using the cost which he buys every thing

 

        cout<<total<<endl;

    }

    return 0;

}

Taum & B'day Hackerrank Solution in C++

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